CROSS LIGHTS · INVESTIGATION

A working press plan is not yet a shortest plan

Exhaust all 32 first-row choices to compare four different solutions to the same diagonal-light board.

Cross presses toggle side neighbours; ● on, ○ off
C1C2C3C4C5
R1
R2
R3
R4
R5
Only the five main-diagonal squares are lit. A press toggles itself and its side neighbours; it never toggles diagonals.

What is the fewest number of presses needed?

Make a prediction before opening the reasoning.

Compare the predictions
  1. Three presses.

    Not supported. The complete first-row enumeration contains no solution with fewer than five presses.

  2. Five presses.

    Supported. The diagonal plan works, and all four possible press sets have lengths 5, 13, 13 or 21.

  3. A working plan cannot ever be proved shortest.

    Not supported. Finite exhaustive coverage can prove a minimum for this exact board.

Predictions stay on this page; they are not saved or sent.

The position and the question

Pressing the five lit diagonal squares clears this particular board. That gives an upper bound of five presses: we know a five-press finish exists. To call it shortest, we must also exclude every shorter possibility.

This investigation uses the ordinary 5 × 5 cross rule and the goal of all lights off. Press order does not alter the final pattern, and pressing a square twice cancels its effect. Therefore a shortest plan presses each chosen square once.

Show the reasoning
  1. Verify the five-press candidate

    Press R1C1, R2C2, R3C3, R4C4 and R5C5. Each diagonal square is toggled once. Every side-adjacent square between neighbouring diagonal presses is toggled twice, so it returns to off. All other squares are untouched. The whole board is dark.

    Cross presses toggle side neighbours; ● on, ○ off
    C1C2C3C4C5
    R1
    R2
    R3
    R4
    R5
    All five diagonal buttons pressed once: every light is off.
  2. Reduce all plans to 32 cases

    There are 2⁵ = 32 subsets of buttons in the first row. Once a subset is chosen, each lit square in row 1 forces the press directly below it. Repeat down the board. A completed first row cannot be affected by presses below row 2, so the chase makes every later row of presses compulsory for that first-row choice.

  3. Keep only chases that finish

    Exactly four first-row subsets yield an all-dark board. They are {C1}, {C3,C5}, {C2,C4,C5} and {C1,C2,C3,C4}. Their complete chase plans contain 5, 13, 13 and 21 presses respectively. The other 28 first-row choices leave at least one light in the final row.

  4. Turn enumeration into a minimum proof

    Every press set has one of those 32 first rows, and the rest of a successful set is determined by chasing. We have therefore covered every parity-distinct solution, not just a sample of routes. The smallest successful set contains five presses. Repeated presses cannot improve it because deleting a repeated pair leaves the same final board with fewer presses.

The tempting shortcut

The first working chase must be the shortest one.

Where the shortcut breaks

A solver that stops at the first solution does not automatically compare lengths. On other boards, a later first-row choice may use fewer presses.

A better decision

Count every successful chase when claiming a minimum, and explain why the enumeration covers all press sets.

Changed conditions

In a mathematical toggle experiment, append two presses of R3C3 to the five-press solution. Is the resulting seven-press sequence shortest? (The live game may stop accepting presses when the board is solved.)

Check the changed-condition answer

The added pair leaves the final mathematical light pattern unchanged: two identical toggles cancel. Removing the pair gives the original five-press solution, so the seven-press sequence is not shortest. This compares toggle sequences, not controls available after a game has ended.

Take this back to your next game

A constructive route proves that a goal is reachable. A complete covering argument is what turns a good route into an optimality proof.

How the claim was checked

Enumerate all 32 first-row masks, chase each, and apply every returned press plan independently.

  • 4 successful masks: 1, 20, 26, 15
  • Solution lengths: 5, 13, 13, 21
  • All 4 plans finish dark

Read the fixed positions and supporting proof data. Computational checks establish only the claim and position stated here. They do not establish a player difficulty rating or make an unproved strategy optimal.

Playfield Arcade · Updated 4 October 2026 · Original case design, AI-assisted writing and code, with reproducible position checks. Our method · Report a correction