CHALLENGE 1

Bridges study 4

ID: bridges-04 · Board: bridges-2027-07-15

Bridge networkA–C: 0 or 1 or 2 bridges; B–F: 0 or 1 or 2 bridges; B–A: 0 or 1 or 2 bridges; C–D: 0 or 1 or 2 bridges; E–C: 0 or 1 or 2 bridges; F–E: 0 or 1 or 2 bridges; F–G: 0 or 1 or 2 bridges; H–G: 0 or 1 or 2 bridges; H–I: 0 or 1 or 2 bridges; I–D: 0 or 1 or 2 bridgesA4B3C6D3E2F2G3H2I1

Explain one move you can prove. Which displayed clue or rule supports it?

Reason: ____________________________________________________

___________________________________________________________

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CHALLENGE 2

Bridges study 5

ID: bridges-05 · Board: bridges-2027-07-28

Bridge networkA–C: 0 or 1 or 2 bridges; A–F: 0 or 1 or 2 bridges; B–E: 0 or 1 or 2 bridges; B–A: 0 or 1 or 2 bridges; C–G: 0 or 1 or 2 bridges; D–C: 0 or 1 or 2 bridges; E–D: 0 or 1 or 2 bridges; E–H: 0 or 1 or 2 bridges; F–H: 0 or 1 or 2 bridges; H–G: 0 or 1 or 2 bridgesA5B2C5D3E1F2G3H3

Explain one move you can prove. Which displayed clue or rule supports it?

Reason: ____________________________________________________

___________________________________________________________

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CHALLENGE 3

Bridges study 6

ID: bridges-06 · Board: bridges-2027-07-25

Bridge networkA–B: 0 or 1 or 2 bridges; A–C: 0 or 1 or 2 bridges; B–G: 0 or 1 or 2 bridges; C–D: 0 or 1 or 2 bridges; D–G: 0 or 1 or 2 bridges; D–F: 0 or 1 or 2 bridges; E–J: 0 or 1 or 2 bridges; E–A: 0 or 1 or 2 bridges; H–B: 0 or 1 or 2 bridges; I–F: 0 or 1 or 2 bridges; J–H: 0 or 1 or 2 bridges; J–D: 0 or 1 or 2 bridgesA6B5C3D3E3F3G2H3I2J2

Explain one move you can prove. Which displayed clue or rule supports it?

Reason: ____________________________________________________

___________________________________________________________

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ANSWER 1

Bridges study 4

ID: bridges-04 · Board: bridges-2027-07-15

Bridge networkA–C: 2 bridges; B–F: 1 bridge; B–A: 2 bridges; C–D: 2 bridges; E–C: 2 bridges; F–E: 0 bridges; F–G: 1 bridge; H–G: 2 bridges; H–I: 0 bridges; I–D: 1 bridge××A4B3C6D3E2F2G3H2I1

Two checkpoints in the solution

  1. Island A needs 4 individual bridges. Its routes currently allow 0 to 4 in total. Holding the other routes within their limits restricts A–C to 2; B–A to 2. A domain “1 or 2” proves a connection but does not yet choose single or double.
  2. A–C is established with at least one bridge. H–I cross that route between islands, so they must carry zero bridges.

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ANSWER 2

Bridges study 5

ID: bridges-05 · Board: bridges-2027-07-28

Bridge networkA–C: 2 bridges; A–F: 1 bridge; B–E: 0 bridges; B–A: 2 bridges; C–G: 1 bridge; D–C: 2 bridges; E–D: 1 bridge; E–H: 0 bridges; F–H: 1 bridge; H–G: 2 bridges××A5B2C5D3E1F2G3H3

Two checkpoints in the solution

  1. Island A needs 5 individual bridges. Its routes currently allow 0 to 6 in total. Holding the other routes within their limits restricts A–C to 1 or 2; A–F to 1 or 2; B–A to 1 or 2. A domain “1 or 2” proves a connection but does not yet choose single or double.
  2. A–C is established with at least one bridge. E–H cross that route between islands, so they must carry zero bridges.

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ANSWER 3

Bridges study 6

ID: bridges-06 · Board: bridges-2027-07-25

Bridge networkA–B: 2 bridges; A–C: 2 bridges; B–G: 1 bridge; C–D: 1 bridge; D–G: 1 bridge; D–F: 1 bridge; E–J: 1 bridge; E–A: 2 bridges; H–B: 2 bridges; I–F: 2 bridges; J–H: 1 bridge; J–D: 0 bridges×A6B5C3D3E3F3G2H3I2J2

Two checkpoints in the solution

  1. Removing D–F would split the graph of all still-possible routes. Every island must belong to one network, so D–F must carry at least one bridge. This does not by itself decide between one and two.
  2. Removing I–F would split the graph of all still-possible routes. Every island must belong to one network, so I–F must carry at least one bridge. This does not by itself decide between one and two.

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