PAPER PRACTICE
Bridges: Count the available bridges
Three fixed studies, followed by separate answer pages. The links and IDs match the online collection.
Join nearest visible islands horizontally or vertically with zero, one or two bridges per route. A bridge cannot pass through an island or cross another bridge between islands. Each island’s number counts individual bridges, and all islands must belong to one connected network.
Use your browser’s Print command or Save as PDF. Both A4 and US Letter fit the diagrams. To keep answers separate, print only the challenge pages. The answer pages contain two useful checkpoints; the online practice page contains the complete checked route.
CHALLENGE 1
Bridges study 1
Explain one move you can prove. Which displayed clue or rule supports it?
Reason: ____________________________________________________
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CHALLENGE 2
Bridges study 2
Explain one move you can prove. Which displayed clue or rule supports it?
Reason: ____________________________________________________
___________________________________________________________
CHALLENGE 3
Bridges study 3
Explain one move you can prove. Which displayed clue or rule supports it?
Reason: ____________________________________________________
___________________________________________________________
ANSWER 1
Bridges study 1
Two checkpoints in the solution
- Island A needs 4 individual bridges. Its routes currently allow 0 to 4 in total. Holding the other routes within their limits restricts A–F to 2; B–A to 2. A domain “1 or 2” proves a connection but does not yet choose single or double.
- Island B needs 3 individual bridges. Its routes currently allow 2 to 4 in total. Holding the other routes within their limits restricts B–C to 1. A domain “1 or 2” proves a connection but does not yet choose single or double.
ANSWER 2
Bridges study 2
Two checkpoints in the solution
- Removing F–D would split the graph of all still-possible routes. Every island must belong to one network, so F–D must carry at least one bridge. This does not by itself decide between one and two.
- Removing G–F would split the graph of all still-possible routes. Every island must belong to one network, so G–F must carry at least one bridge. This does not by itself decide between one and two.
ANSWER 3
Bridges study 3
Two checkpoints in the solution
- Removing A–B would split the graph of all still-possible routes. Every island must belong to one network, so A–B must carry at least one bridge. This does not by itself decide between one and two.
- Removing A–C would split the graph of all still-possible routes. Every island must belong to one network, so A–C must carry at least one bridge. This does not by itself decide between one and two.